DDB

Description: Returns the asset depreciation for a specified period using the double-declining balance method, or another method you specify.

Syntax: DDB(Cost, Salvage, Life, Period, [Factor])

Cost is the initial cost of the asset.
Salvage is the value at the end of the depreciation (sometimes called the salvage value of the asset). This value can be 0.
Life is the number of periods over which the asset is being depreciated (sometimes called the useful life of the asset).
Period is the period for which you want to calculate the depreciation. Period must use the same units as life.
Factor is the rate at which the balance declines. If factor is omitted, it is assumed to be 2 (the double-declining balance method).
All five arguments must be positive numbers.

Remarks:

The double-declining balance method computes depreciation at an accelerated rate. Depreciation is highest in the first period and decreases in successive periods. DDB uses the following formula to calculate depreciation for a period:

Min((cost - total depreciation from prior periods) * (factor/life), (cost - salvage - total depreciation from prior periods))

Change the Factor if you do not want to use the double-declining balance method.
Use the VDB function if you want to switch to the straight-line depreciation method when depreciation is greater than the declining balance calculation.

Example:

Suppose a factory purchases a new machine. The machine costs $2,400 and has a lifetime of 10 years. The salvage value of the machine is $300. The following examples show depreciation over several periods. The results are rounded to two decimal places.

DDB(2400, 300, 3650, 1) = $1.32 [the first day's depreciation. The software automatically assumes that factor is 2.]
DDB(2400, 300, 120, 1, 2) = $40.00 [the first month's depreciation]
DDB(2400, 300, 10, 1, 2) = $480.00 [the first year's depreciation]
DDB(2400, 300, 10, 2, 1.5) = $306.00 [the second year's depreciation using a factor of 1.5 instead of the double-declining balance method]
DDB(2400, 300, 10, 10) = $22.12 [the 10th year's depreciation. The software automatically assumes that factor is 2.]